How to make "5" recognised as an int?

[jc94062]

I'm trying to use gettype to check people passwords, ie disallow ones without a couple of letters/couple of numbers in the end.
However for some reason I've hit a big problem...

$foo = "3.14";
print gettype ($foo); //gives string

$foo = '3.14';
print gettype ($foo); //gives string

$foo = 3.14;
print gettype ($foo); //gives integer

The method I'm trying to use to grab it out of the password is just

$alpha = 0;
$beta = 0;

for ($i=0; $i<=$length; $i++) {
if ((gettype ($split[$i])) == "string") {$alpha = "1";}
elseif ((gettype ($split[$i])) == "integer") {$beta = "1";}
}

echo "alpha: $alpha";
echo "beta: $beta";

Whatever I put in for the password, alpha is 1, beta is 0, even if I put in 46546574 :-(

I'm sure its due to the '' / "" problem, I just can't figure out how to fix it.

[khaine]

the gettype will return a string because of the quotes a way round is to use the is_numeric function. It returns true in the value is numeric even if it is in a string.
Your program would look like.

$alpha = 0;
$beta = 0;

for ($i=0; $i<=$length; $i++)
{
if ( !is_numeric($split[$i]) )
{
$alpha++;
}
else
{
$beta++;
}
}

echo "Numeric in string :".$beta."<BR>";
echo "Alpha in string :".$alpha."<BR>";

Mark.

[jc94062]

Thanks! Works great now!