Go to other site by "select"

[Anon]

Dear all,

I want to write the html code to link to other website by opening new window.

The code is below

<select name="menu2">
<?while (list($ch_name,$website)=mysql_fetch_row($result)):?>
<?if (trim($website)!=""){?>
<option value="http://<?echo trim($website)?>"><?echo trim($ch_name)?>
</option>
<?}endwhile?>
</select>

However, the new website can be linked in the same frame but not in the new window frame. Please give me solution how to open the window frame, thanks

Simon

[jesus_hairdo]

do you have a dropdown box of different sites, when they click on the name you want that site to open in a new window, is this correct ?
I suspect you will need to use a bit of javascript and event handling, if you go to http://javascript.internet.com they have examples here on how to do this.

Jamie

[Anon]

Yes, I have a dropdown box of different sites, when they click on the
name I want that site to open in a new window.
Please give me help, thanks

[jesus_hairdo]

If you go to this link it will show you how to do the drop down menu. the only bits you'll need change is the value's of the <option> tags

http://javascript.internet.com/navigation/men
u-popup.html