Upload script takes passed variables??

Anon

Hi!

I am calling the script below using
upload.php?filename=d:\files\myfile.zip
but it doesn't seem to work. The local file exists and the destination folder has all the correct permissions set. Is there any
reason why I shouldn't be able to pass the
filename of the file I want to upload in this
way? Even if I set $filename to the local filename within the script, it still doesn't seem to work.

Help!

<?php

$my_max_file_size = "307200"; # in bytes
$image_max_width = "300";
$image_max_height = "300";
$the_path = "../jls2/uploads";

function upload($the_file) {

global $the_path,$the_file_name;

if (!@copy($the_file, $the_path . "/" . $the_file_name)) {
	print "\n<P><b>ERROR</b>";
} else {
	print "\n<P><b>OK</b>";
}

} # END upload

print "\n<head>\n<title>Upload File</title>\n</head>\n<body>";

upload($filename);

print "\n</body>\n";

Anon

I dunno, but you can't post pictures without using the <form> atributes method="post" and enctype="multipart/form-data"

thats my experience.

amsowe

How do u call the function?
What variables do u pass exactly?

Anon

I'm using upload($filename);