Function arguments

Anon

Is there some doc about writting functions with variable number of parameters so that for example i can call one like this:

ShowField (Type="text", Length=40) etc...

Parameters are optional arguments...

Thx.

Anon

Parameters in PHP are not optional arguments. If you want to pass in a variable number of parameters then you'll need to put them in an array and just pass in the array.

$field_options["type"] = "text";
$field_options["length"] = 40;

showField($field_options);

Anon

Thx. for reply but that's not what i wanted. I just want to call my function with parametars as:

ShowField (Type="text", Width=40, Case="Upper")

I don't want to call it with $field_options array. It's the same as when u have some aplication and u call it for example pine and then come the arguments ... So, i want to call my function like that? How can this be done?

Anon

Like I said you can't do that for a function. You have to build the function with a set number of parameters and then call the function with a set number of parameters. If you want to build an entire PHP script that runs from the command line and takes in parameters like a standard Unix program does you can do this, but all that happens is that PHP puts all of your arguments into an array that you then have to deal with.

Anon

I made something like: function showfield()
and i call it showfield ('Type=text', 'length=40', ... )Then i do some checking of parameters with string functions in showfield function...

Anon

I'm sorry I just went to php.net and read the functions section in the manual, apparently in PHP4 you can do what you want to do, I didn't know that.

Anyway your function should look something like:

showfield($args) {
for ($ndx = 0; $ndx < $num_args; ++$ndx)
$curr_arg = func_get_arg ($ndx);
// do something with $curr_arg
}