switch statement loop

[Anon]

why won't this work? I get the following error:
Parse error: parse error, expecting T_CASE' orT_DEFAULT' or `'}'

can I not say $subMenu($j+1) to make it $subMenu1, $suBMenu2, etc? or is the problem elsewhere?

for($i=0; $i < count($mainMenuItems); $i++) {
if($main == $i)
$button = 2;
else $button = 1;
switch ($i) {
for($j=0; $j < 6; $j++) {
case $j:
$subMenu = $subMenu($j+1);
break;
}
}
print some stuff;
}

[ace21]

use
$submenu = $submenu.($j+1)

the dot is used to combine two strings, which I believe is what you are trying to do.

Ace21

[[deleted]]

"can I not say $subMenu($j+1) to make it $subMenu1, $suBMenu2, etc?"

No, not like that.

Read the manual about variable variables:
http://www.php.net/manual/en/language.variables.variable.php

[Anon]

eval("\$subMenu = \$subMenu".($j+1).";");

[Anon]

ok none of that worked, but it might have something to do with the fact that i failed to mention that $submenu0, 1, 2, etc. are all arrays, I wanted to set $subMenu = $subMenu(whichever menu is called). I have it working writing out each case, which is fine, but I wanted to make the code shorter if possible. hope this clarifys.

[[deleted]]

Why not change the submenu into a multidimensional arrau, and use the 0,1,2 to point to the first level of the array:

$aArray = array();
$aArray[0] = array('menu1_item1', 'menu1_item2');
$aArray[1] = array('menu2_item1', 'menu2_item2');
$aArray[2] = array('menu3_item1', 'menu3_item2');

echo $aArray[1][2];