Simple help with an "IF" statement

Anon

Ok, obviously this code is wrong, but if you look at it i think you will understand what i'm trying to do. Could someone give me the correct way to do this.

<?php

$a=1;
$b=2;
$c=3;

if($id != $b OR $c)
{
$id=$a;
}

echo $id;

my problem is with the "if($id != $b OR $c)"
i guess you can't put an OR in it so what do i do?

thomas2

if(!$id = $b OR $c)
{
$id=$a;
}

Should do it.

knickerlas

use || like this

<?php

$a=1;
$b=2;
$c=3;

if($id != $b || $id != $c)
{
$id=$a;
}

echo $id;

Should work fine, you may have to put the individual expressions in braces as well though like this

if(($id != $b) || ($id != $c))

I never seem to know first off whether I need do that?

Nick

Anon

Sorry guys, i might be doing something wrong, but neither of those worked. I'm just going to use the switch case and the default function. I read up on it some, and that will work better for me anyways. Thanks

peace
sean

mixx22

try this:

<?php

$a=1;
$b=2;
$c=3;

if(($id != $b) OR ($id != $c))
{
$id=$a;
}

echo $id;