converting # to word form>??

[Anon]

How can i convert numbers to be formatted with the proper word.

example

2 i want to to sho 2nd

13 i want to show 13th

42 i want to show 42nd

etc

is this possible?

[hessian]

I think if you cant find a better solution, you could also jerry rig the date() function to do this for you.

http://www.php.net/manual/en/function.date.php

If you are using it for a date, even better.

[Anon]

This doesn't seem too hard. We know the following:

1 - 1st
2 - 2nd
3 - 3rd
4 - 4th
5 - 5th
6 - 6th
7 - 7th
8 - 8th
9 - 9th
10 - 10th

Basically, you can write a simple function that consists of nothing but a big if-then/else or set of case statements. You could be pulling the number from a db or from user input, whatever. Once you get it, analyze it and the manipulate it. Something like

function format_num($sNum)
{
$len = strlen($sNum);
$sLast_Dig = substr($sNum, $len - 1);
$sFormatted_Num = "";
switch ( $iLast_Dig )
{
case 1:
$formatted_num = $sNum . "st";
break;
case 2:
$formatted_num = $sNum . "nd";
break;
//etc...
}
return $formatted_num;
}
Now I didn't actually check this to see if there are any bugs, but the concept is there. Hope this helps.

[alfbennett]

This sort of Idea would work great too

function get_numbered($integer){
$0 = 0th
$1 = 1st;
$2 = 2nd;
$3 = 3rd;
$4 = 4th;
$5 = 5th;
$6 = 6th;
$7 = 7th;
$8 = 8th;
$9 = 9th;
$10 = 10th;
$11 = 11th;
$12 = 12th;
$13 = 13th;
$14 = 14th;
//etc..
return $$integer;
}
You could run some sort of check that gets the last digit from an integer (treated like a string) to set the proper th, rd, nd to the end of the number for nubers over 19. The person who set up variable variables for PHP should be kissed. No if or case statement needed. Hope this helps.
Alfred