javascript in PHP probs

Anon

hi there,

Can anyone tell me if there is some rule to placing JS within PHP. I'm still quite new to this programming lark, but can't find anything that solves my problem in the manual or the support sites.

Basically, I want to use a rollover image as a submit button in a form.

The image as a submit button works fine:

As does the rollover script when placed outside PHP.

But everything goes belly up when I try to combine the two.

I can't solve this by using frames or anything 'cause it's obviously got to exist within the form.

Please Help...

frigidman

Try to "end" the PHP right before the javascript chunk and then "begin" the PHP again right after.

<?PHP
...some php code;
...more php code;
?>
raw javascript code
<?PHP
...more php code;
echo "<A HREF=\"link\" onmouseout=\"javascriptfunction\" onmouseover=\"javascriptfunction\"><img src=\"location\" name=\"something\"></A>";
?>
etc
etc

You can stop and start the PHP anywhere and almost anytime in a PHP. You can even stop it right in the middle of IF() {} ELSEIF() {} ELSE {} etc. Very handy for when you might have huge chunks of html you REALLY dont want to go digging through escaping doublequotes and the like.

emcb_php

Hi,

You cant use a image input tag to contain a rollover unless you do it as an onMousover like:

...
<input type="image" src="/images/some.button.gif" onMousover="doRollOver();">

Elfyn

rhannamgmxnet

i know u posted this a while ago and wasnt sure if u found a soultion i had the same problem today i fixed it by applying this.src to the onmouseover/onmouseout attribute instead of defining the whole path (document.imagename.src)

although this only works in IE not in Netscape as apparently netscape see this tag as a submit button not an image

hope you fix it...

jo wrote: