Simple If syntax problem...

Anon

I keep getting parse errors, I am new to PHP what is wrong with this short script? Above this I have a form with the following line...

then below by php script

The server is currently
<?php
if $name=Vortex;
}
?>
<b>online</b>
<?
}
else
}
?><?
<b>offline</b>
}
?>

[deleted]

You might want to use opening and closeing {} brackets:

if (1==2)
{
// yes
}
else
{
// no
};

Anon

still getting a parse error, here is my new statement using what you said...

The server is currently<?php
if ($name == Vortex)
{
<b>Online</b>
}
else
{
//<b>Offline</b>
};
?>

Anon

Ok I got it working, here is my new code, but I have yet another problem...

The server is currently <?php
if ($name==Vortex)
{
?>
<b>Online</b>
<?
}
else
{
?>
<b>Offline</b>
<?
};
?>

Ok now again above this code in the php file I have a form and in the form I have the following line

The form keeps saying offline now, shouldn't it say online with the script above and given that line in the form?

amcgrath

grrr.... here:

<?php
if ($name="Vortex") {

?>
online
<?
} else {
?><?
offline
}
?>

amcgrath

double the == while you're at it

Anon

Thank you works great!!!

amcgrath

well, while you use it, you might want to take a minute and compare it against your original. There are a number of mistakes in your original file, and you can use this as a chance to learn the proper syntax....

Anon

Oh I definately have, the major learning here for me was the proper syntax for the if statement when dealing with a variable from a form, I really needed that one. Thanks!

Anon

I am going to kill myself, what I thought worked does not... here is the page I am testing with if you want to take a look...

http://vortexserver.f2g.net/serverstatus.php

Of course the php code is not visible but the line <input type=.... is in there and you can see the value is Vortex, again here is my code...

<?php
if ($name == "Vortex") {
?>
online
<?
} else {
?>
offline
<?
}
?>

Anon

Where do you submit the form to the script?

Anon

PS
http://vortexserver.f2g.net/serverstatus.php?name=Vortex
works just fine

Anon

I am not submitting the form, I thought I could just add that invisible line and the php would recognize the value... am I wrong?

Here is some other information that should help, this game server has a proprietary code that spits out a html file, I can put commands like %SERVSTAT% in the html code and the html will output Vortex

so actually I have %SERVSTAT% as the value in the form, it works as I see Vortex in the online form you see!

mike_y

In short, when you have a hidden <input>, it's the same as any other <input>. You have to submit the whole form, and on the page that you submit it to (which is your action="" in the form) you can use that variable.
I still don't understand why you want to do it that way though.
Can you do something like
if(%SERVSTAT% == "Vortex")
echo "online"; ?

Anon

Yeah playing with that notion now ;-)

Anon

Thanks everyone it finally works great!!!

Anon

Weeeee ....

just wanted to ride this bad boy

Anon

some text here