Displaying images

[Anon]

I am trying to write a script that will display 3 images on a table row, and then goto the next table row, and display 3 more images, but I can't figure out how do this using the mysql_fetch_array statement. Can anybody help. I know how to make it put one image on a row and goto the next, but I want to put 3 different images on a table row.

[paha77]

use a counter and a temporary variable in w
while statement. something like that

$counter = 0;
$temp = "<tr>";
while ($row = mysql_fetch_array(...))
{
$temp .= "<td>...</td>";

if ($counter == 2)
{
$temp .= "</tr>";
print $temp;
$temp = "<tr>";
$counter = 0;
}
else
{
$counter++;
}
}

[Anon]

Thanks,
That did the trick...