To solve copy and upload questions

[Anon]

Hi :
I've some codes and i hope it's can help everyone to solve about copy() functon and upload questions.
following list my base code:

global $configDefaultUploadPath ;
$file_type = strrchr($images,".");
if($file_type ==".gif" || $file_type == ".jpg" || $file_type == ".jpeg")
{
$image = strrchr($images,"\");
copy($images,$configDefaultUploadPath.$image);
}
else
{........}
And $configDefaultUploadPath is a global variable.it's mean desc location.you can set it like :
$configDefaultUploadPath="../uploads";
And strrchr() is to get your source file name.
If everyone have any question .. you can mail to me....

[rrijnders]

http://www.php.net/manual/en/features.file-upload.php

[Anon]

$file_type = strrchr($images,".");
if($file_type ==".gif" || $file_type == ".jpg" || $file_type == ".jpeg")

That won't work.. strrchr return the position where needle is found, not a substring.
You should have something like:
$file_type = substr($images, strrchr($images,"."));

[Anon]

$file_type = strrchr($images,".");
if($file_type ==".gif" || $file_type == ".jpg" || $file_type == ".jpeg")

It's can be work . $images is <input type="file" name="images"....> 's name.
And strrchr() in my code is to get this upload file type. so i think it can be work
.If you have any question .. i think we can talk about it ...

Anders wrote:

$file_type = strrchr($images,".");
if($file_type ==".gif" || $file_type == ".jpg" || $file_type == ".jpeg")

That won't work.. strrchr return the position where needle is found, not a substring.
You should have something like:
$file_type = substr($images, strrchr($images,"."));

[Anon]

Still, strrchr will leave a number (int) in $file_type,
not a string.

Perhaps you should post a little bit more of your script so that I'd get a better understanding of it.

[Anon]

$images is "<input type="file" name="images">
name.so
$file_type=strrchr(".",$images);
and you'll get this file type. like gif,jpeg
...type.
I set $file_type that because i need to check upload file type is images file.so i do it.
if you did't need it. You can cancel it.
I hope it's can help you.

[angulion]

First of all, it is in my opinion easier to use $HTTP_POST_FILES['images']..
so you would like to have something like:
$img = $HTTP_POST_FILES['images'];
$ext = substr($img['name'], strrchar($img['name'], "."));
echo "File extension is: ".$ext."<br>\n";
Now $ext will be gif/jpg/something..