how to get the content of an URL?

paulchen

Hi all:
Could anybody tell me how to get the content of an URL? Suppose we have "http://www.cnn.com", how can I get the whole source code of that html page. I have written some pieces of code, could anybody fix it to work well?
My code:
<?php

$handle =@fopen("http://www.realdecoy.internal/","r");
if ($handle)
{ print"The file exists!"; }
else
{ print"The file does not exist"; }
$size=filesize ("http://www.realdecoy.internal");
$contents = fread ($handle, $size);
echo "HTML is: $contents";
fclose($handle);

Thanks in advance.

Paul

Anon

Use a parser that copies the first character to the last character and then saves it as a file

matto

try file() instead of fopen-fread-...
it works with most pages.

paulchen

Hi,jennifer:
Could you give more detail. Because I am new in PHP, could you fix my code?

Paul

paulchen

Hi,all:
I solved it. Thanks anyway.

// get a web page into an array and print it out
$fcontents = file ("http://www.php.net/");

while (list ($line_num, $line) = each ($fcontents)) {
echo "Line $line_num:; " . htmlspecialchars ($line) . " \n";
}

Thanks in advance.

paul

paulchen

Hi,jennif:
I solved it. Thanks.

// get a web page into an array and print it out
$fcontents = file ("http://www.php.net/");

while (list ($line_num, $line) = each ($fcontents)) {
echo "Line $line_num:; " . htmlspecialchars ($line) . " \n";
}

Hope get your help later, because I am doing a security project, which use Perl & PHP & PostgreSQL, as well as, I am pretty new in PHP, never use PHP before. So please continue to help me later.
Thanks in advance.

paul