host name to country name?

[jackonline]

I need little help:

I got host name - visitor on my website and than I want to assign each host addr to domain country.

//$host = gethostbyaddr ($host_addr);

example
$host -> $host_addr -> [.xyz]country name
4.17.253.215 -> chi-tnt-ppp215.mw.sisna.com -> [.com] Commercial Users

or
213.76.50.32 -> pc32.bydgoszcz.cvx.ppp.tpnet.pl -> [.pl] Poland

...

Anyone can help with coding or point me to the right direction ?

http://www.temperaments.com

[Anon]

$array = explode(".", $host_addr);
$top_domain = $array[sizeof($array)-1];

Now you've got the top domain. To output the country you could make a query to a database or read a file with domains into an array? And then run through the array until you find that domain.

Sounds like it could work. 🙂

[Anon]

How to find the host:

<?php
$host_addr = "";

if (getenv(HTTP_X_FORWARDED_FOR)) {
$host_addr=getenv(HTTP_X_FORWARDED_FOR);
} else {
$host_addr=getenv(REMOTE_ADDR);
}

$host_addr = gethostbyaddr($host);
?>

An easier? way to output the country:

<?php

$country = "";

switch($top_domain) {
case 'com':
$country = "Commercial";
break;
case 'pl':
$country = "Poland";
break;
// etc...
default:
if (is_numeric($host_addr))
$country = "Not a domain."; / host is an ip-address /
else
$country = "Unknown domain."; / domain not listed above /
}

?>

[jackonline]

Thanks Dag 🙂
It is working perfectly,

my code:

$host = gethostbyaddr ($host_addr);
// From ? //
$array = explode(".", $host);
$top_domain = $array[sizeof($array)-1];
$country = "";

switch($top_domain) {
case 'com':$country="Commercial";break;
case 'arpa':$country="ARPANet";break;
case 'edu':$country="Education";break;
case 'gov':$country="Government";break;
// etc ..

default:
if (is_numeric($host))
$country = "Not a domain."; / host is an ip-address /
else
$country = "Unknown domain."; / domain not listed above /
}

// end From ? //

JackOnline
Internet International
http://www.internetintl.com