array_walk problem

[zazulas]

Hi !

I would like changes made on elements within array_walk to be reflected in the array itself. There is a note in PHP manual:

"If func needs to be working with the actual values of the array, specify that the first parameter of func should be passed by reference. Then any changes made to those elements will be made in the array itself"

Can you please give me an example how to pass results from the user-defined functions to the array itself ???

Ziggi

[Anon]

<?php
$my_array = array(1,2,3);
do_something($my_array);

function do_something(&$array) {
$array = array(4,5,6);
}
?>

because of the & before $array in the function definition, the item will be passed by reference, so $my_array after the function is called will be an array with values 4,5,6.

[zazulas]

Thank you !

This is the right answer !

Hereunder please find the working example:

function trimm(&$value){
$value = rtrim($value);
$value = ltrim($value);
}

$osoby = array("John ", "Marry", " Andrew", " Bob ")
reset($osoby);

array_walk($osoby, 'trimm');

The after code execution array $osoby will contain: "John", "Marry", "Andrew", "Bob".

That means leading blank spaces were trimmed.

Thank you once again Michael!
Ziggi