Passing arrays through a function

[axsdeny]

I'm calling a function from an included file. This function stores database info in an array. This array is then returned.

How do I echo individual elements of the array? I don't quite understand how variables are passed through functions so any help if welcome. i am currently simpky doing this:

ECHO myfunction();

This does nothing... I want to display individual values that are in the return array.

[amcgrath]

if the array you have is called $myfunction, then just loop through it to see whats in it. This:

while(list($k,$v) = @each($myfunction)) {
echo $k . "=" . $v;
}

where $k is the key, $v is the value.... the manual explains in more detail about suing arrays, btw...

[bfinucan]

Hello,
So you have a function that returns an array. If you are familiar with calling arrays indices, it's easy to get the values you're after.

Example:

function dbInfo() {
$sql = "SELECT id, name FROM table WHERE id=1";
$result = mysql_query($sql);
//let's say you're just grabbing a single row
$row = mysql_fetch_array($result);

return $row;
} //end dbInfo()

//place returned result into variable
$data = dbInfo();

//now print the id column
echo ($data[id]);

//or print everything
foreach ($data AS $col) {
echo $col . "<br>";
} //endforeach

//or print the structure of your array to see what you have (depends on PHP version)
print_r($data);

[majik-sheff]

That probably won't work like you think it will. This is a better approach:

$myResult = myfunction();
while(list($k,$v) = @each($myResult)) {
echo $k . "=" . $v;
}

Good luck 🙂

[axsdeny]

I love you.

[[deleted]]

lol
such a hartwarming post... yes it's allmost christmas time... 🙂

[majik-sheff]

What a wonderful world. 🙂 Ok, I'm done being off topic now.

[amcgrath]

not to be picky, but I began it with "if the array you have is called $myfunction..." but i can see where he might get a bit confused...

[[deleted]]

lol