The same thing, I have following php code:
-- begin php --
if(xslt_transform('arg:/stylesheet', 'arg:/spec', 'arg:/', false,
array(
'stylesheet' => $stylesheet,
'spec' => $spec,
'JS' => JS_XSLT
), $result)) {
return $result;
}
-- end php --
I have <xsl:include href="arg:/JS"/>, it tells me "Wrong expression syntax", does this problem have solution?
