pattern matching

jhaskins

I'm in the process of creating a "members only" area of my site. For the purpose of convenience, I plan on using the member files from our UBB for login info so there is 1 login that works for everything. I have the code I need to open the appropriate member file, check if the member has access to a private forum (those with access are the ones that will be using the members area) & get the username & password. Here's where I run into a problem. The username entered into the script will be just that, a username. UBB names the member files by member number (ie 00000001.cgi). This means that I have to translate the login name into a member number. I plan on doing that using a file that UBB creates that stores login name & member number pairs. The format it uses is

user1|!!|00000001
user2|!!|00000002

and so on like that. Using the username that was entered, how would I 1)See if it is listed in the file & 2)If it is, get the member number and assign it to a variable.

Any help would be much appreciated.

whizkid

Hi,

Try this:

function get_user_id($name) {
$string = join('',file('URL_TO_FILE')); //URL to the file where the userdata is stored

$a = explode("\n", $string);
$member = array();

while (list(, $value) = each ($a)) {
$b = explode("|!!|", $value);
$member[$b[0]] = $b[1];
}

if($member[$name] != "") {
return $member[$name];
} else {
return false;
}
}

if(get_user_id("user1") !== false) {
echo "The username exists!";
} else {
echo "The username doesn't exist!";
}

Hope it helps!
firemouse2001

jhaskins

Pardon my ignorance (I'm fairly new to php). How would I get the member number (the part after the |!!|)?

Anon

if($member[$name] != "") {
return $member[$name];
} else {
return false;
}
}

returns the member number that goes with the supplied $name, or false if $name wasn't found.

whizkid

Hi,

You could rewrite the last lines of the Script to:

if(get_user_id("user1") !== false) {
echo "The username exists!";
$uid = get_user_id("user1");
} else {
echo "The username doesn't exist!";
}

If the user exists, $uid will have his number.

firemouse2001