$var help

[Anon]

I am trying to finish a project and need what I am sure is some basic code. I am doing an IF statement to call images based on the $page variable. I want to add a pre-statement that will exclude some of the pages from the dynamic call. So what I need is something like this:

if ($page==var1,var2,var3)
echo("<img src=\"pics/image.gif\">");
else
if ($page)
echo("<img src=\"pics/$page.gif\");
else
echo("<img src=\"pics/welcome.gif\");

If I just have "var1" alone at the top it works fine. I just need to have multiple $page variables listed.

Thanks for any help.

Jim S.

[[deleted]]

use 'or'

if (($page == var1) or ($page == var2) or ($page == var3))
{
//ok
};

[cordex]

<old man>
All this newfangled pseudocode ... imagine, using actual text as an operator!
Why, back in my day, if we wanted to say "or", we just had || ... and we liked it!
</old man>

-Ben

[rrijnders]

LOL! <b>&&</b> Loving It

[[deleted]]

hehe... you like what you have untill you can get something better :-)

[Anon]

Vincent,
Thanks for the tip. Once again something I have seen before that should have been obvious. I am too old to learn new things I guess. 🙂

Jim

[Anon]

If I have a lot of these ($page == "var") pages, is there an easier cleaner (faster?) way to do this operation?

Thanks,

Jim

[[deleted]]

You could put all the options into an array and use in_array() to find it:

$aOptions = array(var1,var2,var3,var4);
if (in_array($page, $aOptions))
{
//yes
}

http://www.php.net/manual/en/function.in-array.php