include();

[Anon]

Is there a way to call a function if a include doesn't work? I tried this:

<?php
include("file.php") or error("Could not open file.php!");

function error ($error) {
print "$error";
}
?>

it didn't work though.

It said this: Warning: Failed opening '1' for inclusion (include_path='.:/usr/share/php') in /home/sites/cgi.e3-web.net/users/test.php on line 2

Any ideas?

[[deleted]]

An include will fail if the file does not exist, so first check if the file exists:

if(file_exists('file.php'))
{
include('file.php');
}
else
{
// do something else;
}

http://www.php.net/manual/en/function.file-exists.php

--
vincent

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