Keeping last digit in a double

[Anon]

I am using php 4 to display money values. My problem is when there is a value and the last digit is a zero, php will not keep that zero. For example if i had $4.50 it will display it as 4.5 and i absolutley need it to be 4.50 . Is this possible. I have tried casting and settype but it seems like it wont keep the last zero.

Any help would be greatley appreciated.

Ira

[Anon]

well, you could write a function that would verify the number of figures after the decimal and then return a string that you can print. like this:

function displayValue($number, $figures) {
$array = explode(".", $number);
while(strlen($array[1]) < $figures) {
$array[1] .= "0";
}
return implode(".", $array);
}

Also, since you're just using it for money values, your function could only take a single parameter and replace $figures (within the function) with the number 2. Then, in your code, just:

echo '$'.displayValue($number);

[whizkid]

Hi,

try this:
$formatted = sprintf("%01.2f", $money);

firemouse2001

[Anon]

yes, that's much better than my idea. nice work.