variable troubles!

adamgeorge

Hi everyone 🙂

I've got a bit of a problem that I can't seem to work out how to do in php.

Here it goes:

I have a set of variables with names like:

$business_name, $address ect.

and I also have another set called
$o_business_name, $o_address ect matching each of the first set.

Now I know that's a strange thing to do, but nevertheless I want to stick with it for now.

So... what I want to do is in my code I pic a varable from the first set due to some algorithm.

eg... $business_name gets picked. I then want to imediatly refer to it's matching variable $o_business_name. How do I do this?

I want to append $o_ to the name of whatever variable gets picked and refer to that new variable name (minus the extra '$' of course)

is that possible? can you modify varable names and then refer to the new variables value in your code?

ha... does anyone even get me? probably not. sorry... I don't explain very well... well.. I hope someone does.

thanks though 🙂

adamgeorge

Whoops!!

made a mistake!

better clarifly things..

I don't want to append '$_o' to the name of a variable... but rather the value of a variable..

hmm... that changes things... silly me.

ok... well..

here's a extract from my code:

for($i=1; $i<$numChecked; $i++){
$selectquery .= ",$collum[$i]";
//$where .= "$o_"."$collum[$i]";
//this bit is stuffed up.
}

hmm... what's going on is i'm trying do dynamicly generate a query for php... it's working ok so far... I just need to add the 'where' clause.

anyway... this bit of code goes through an array which contains the names of the fields in my table... and adds them into the query.
Then... each field in the the array also has a matching variable that holds a value that forms part of the 'where' clause of the query.

eg $collum[2] = 'business_name';

I now want to access the variable $o_business_name and any other varables that match the fields that are in my array using the for loop.

how do I do this?

I hope I haven't made the confusion worse!! ha... but believe me... I know what I want to happen... I just can't work out how to do it....

well.. thanks

Anon

PHP supports variable variables, in other words....Screw the words, look below for an example.

$collum[2] = 'business_name';
$collum[2] = "o_" . $collum[2];
// Since $collum[2] now equals o_business_name

print $$collum[2];
// You are basically printing $o_business_name

Understand?

http://www.php.net/manual/en/language.variables.variable.php

adamgeorge

hmm... in case anyone cares, I've sinced solved the problem....

well... that's not entirley true... I just worked around it 'cause I don't have anymore time to waste... hmm...

well... so this thread wasn't a total waste of time, I'd still be interested in knowing how you can append strings together so you can reference a variable.

eg.

$myvar = 3;

if('$my'.'var' > 3)
&npsp; print"this doesn't work";

it would have been usefull for what i was doing.

ok.. bye 🙂

adamgeorge

oh... it seems I spoke too soon...

thanks man!

I'll try it out

later.
-Adam 🙂