Trapping Errors in PHP?

[Anon]

Hi,

I have this basic template parsing script for my home page, but have a slight problem with it. The script is simply as follows:

if ($page=="") {
include("default");
} else {
include("$page");
};

If there is no 'page=' in the URL, it parses the file 'default', which is the home page.

However, I want the script to display a 404 type page/message should a page in the URL not exist.

i.e. If for whatever reason http://www.mydomain.com?page=about didnt exist, instead of having Warning errors - would it be possible to trap the errors and redirect to index.php?page=404 or something?

The errors I get (within the template) at the moment are:

Warning: open_basedir restriction in effect. File is in wrong directory in /home/httpd/vhosts/mydomain.com/test/index.php on line 56

Warning: Failed opening 'about' for inclusion (include_path='.:/usr/share/php') in /home/httpd/vhosts/mydomain.com/index.php on line 56

Thanks.

[terje-s]

There are numerous ways to do this.

One would be;

---

if (( (int)@include($page) )) {
// include is okay
} else {
// include failed.

}

(Of course, modify to redirect etc. if include fails).

Another method would be to use

if (!file_exists($page)) {
print "File does not exist.";
}

[Anon]

if ($page == null)
{
include ("default.php");
}
elseif (!file_exists($page))
{
header("Location: custom404.html");
exit();
//of course you could direct it at a file
//that doesn't exist on your server and
//let it popup the 404 page itself
}
else
{
include($page);
}