Parse error on line 2

[Anon]

I cannot figure out whats wrong w/ this... Its just a test script to make sure im understaning mysql functions somewhat.
<code>
<? php
function read_poll(&$option1name, &$option2name, &$option3name, &$option4name, &$option5name, &$polltitle, &$option1count, &$option2count, &$option3count, &$option4count, &$option5count, $pollnum){

$dbh=mysql_connect ("localhost", "username", "********")
or die ('I cannot connect to the database.');
mysql_select_db ("central_gamingmv"); 
$query = "SELECT id WHERE id =  '$pollnum' FROM poll";
$result =mysql_query($query){
	or die("Failed")
}
$row=mysql_get_row($result);
$option1name=$row->option1;
$option1count=$row->option1count;
$option2name=$row->option2;
$option2count=$row->option2count;
$option3name=$row->option3;
$option3count=$row->option3count;
$option4name=$row->option4;
$option4count=$row->option4count;
$option5name=$row->option5;
$option5count=$row->option5count;
$polltitle=$row->title;
mysql_close($dbh);

}

$o1n=$o2n=$o3n=$o4n=$pt=$o5n='Test';
$o1=$o2=$o3=o4=$o5=1;
read_poll($o1n, $o2n, $o3n, $o4n, $o5n, $pt, $o1, $o2, $o3, $o4, $o5, 1);
echo "'$o1n' '$o2n'";

?>

[mattw]

<? php

should be

<?PHP

Matt Wade
codewalkers.com

[Anon]

Well, <?php

You also want mysql_fetch_array() instead of mysql_fetch_row() if you want to refer to results by name, and you want $row['option1'] instead of $row->$option1. But it won't have a value either way, since you don't ask for option1 (or any of the others) in the query, only "id", and you already know that.