Open an udp socket help!

Anon

I am trying to open an udp socket using fsocketopen, I 'm testing it by making sure the machine I'm trying to connect to is offline or online. this is the basic code:

$handle = fsockopen("udp://" . cfgServer, $cfgPort, &$errno, &$errstr, 10);
if (!$handle)
{ echo "$errno : $errstr <br/>"; }
else
{
echo "Socket open!";
}

fclose($handle);

My problem is, no matter if socket connects or not it always falls to the "Socket open"

This means that my first if is not working. Does anyone know why it doesn't return FALSE, like the manual says? Any ideas? Thanks

Anon

If you just copy and pasted what your code is, then your problem is a simple matter...

Note your fsockopen, see your $cfgServer variable? You're not using the var, you're using a literal ... follow me? You don't have the $ sign in front to signify it's a variable.

Now ... if that isn't it, post back and we'll go through the code step by step. There's also a article on exactly what you're doing on this site at: http://phpbuilder.com/columns/armel20010427.php3

Enjoy.

Anon

that wasn't a cut and paste, that was a typo, I do have the $ in front of my actual code. I have seen the article. My problem is that if the socket fails to open it should return false, correct? therefore if(!$handle) should be true and fall into the that set of code, but it never does, I put an echo in the if and the else, and no matter if the socket connects, it always goes to the else. why does this not stop at the first if? thats my big problem.