% literal in PHP

[Anon]

How would I go about using the percent sign in php? I want to use it as a literal character, rather than representing a variable. I know with some characters like printing quotes you must escape them before using them, so the compiler doesn't get confused. So how would I get the following output?: "There is 50% more memory"
-Nick

[Anon]

nevermind. If anyone has had this problem, you can simply correct it by just going %%. so you'd get printf("There is 50%% more memory");

[Anon]

Additonal note;

This problem will only occur if you're using the printf() function. In many cases, print or echo will do what you need.