A little annoyance

Anon

I am making my own CMS built in PHP for my own personal sites. Everything so far is going well. I've got news administration, creates pages with text, left and right blocks and a user system, with classes that can tell what state a user is (eg normal, moderator and administrator). But I have got one problem.

Because I have built my site like this:

<?
include (header.php);

mysql content retrieved

include (footer.php);
?>

In Header.php is stuff like sessions, the layout and the left blocks, and in footer.php is the right blocks and end of html.

But, for example, when I add a new block to the left, because the left blocks have already been processed in header.php, it doesn't appear, but the right blocks will, because footer.php is included after the code.

And also with logout/login, cos the header.php has already been processed, at the top of the screen it will say Login instead of "Hello UserName", until i refresh or go to the next page. Can anyone suggest what I should do with this, any ideas? I will be eternally greatful.

Thankyou.

Anon

Simple.

Don't sprinkle your php code into your html.

Run all your MySQL queries in the top of your code. Put your html into variables, then call your header and footer.

Example:

// Connect to MySQL

// Query MySQL

// Put MySQL Queries Into Variables Via Blocks Of HTML

$content .= MySQL Data

// Include Your Headers And Footer

$header = include (header.php);

$footer = include (footer.php);

echo $header;
echo $content;
echo $footer;

This way your html code is not processed until you are ready for it to be.

Make sense?

Anon

but most of the statements are in "while" commands... how am I meant to make the whole code into a variable, exactly?

Anon

<?
$result = mysql_query("SELECT * FROM leftblocks WHERE class<='$userclass'",$db);
if ($myrow = mysql_fetch_array($result)) {
do {
printf("<table border=1 cellpadding=2 cellspacing=0 width=200 bordercolor=#000000><tr><td>%s</td></tr><tr><td>%s</td></tr></table><BR>\n", $myrow["title"], $myrow["content"]);
} while ($myrow = mysql_fetch_array($result));
} else {
echo "Blocks Error (left) . Please contact Administrator.";
}