dynamic drop down box

[Anon]

Hi,

Ive created a drop down box from the contents of a table. I am using the onChange command so I dont have to click a button to start the process. My problem is that i cannot figure out how to pass the variable thru my link:

After I query the database:

echo "<select size=\"1\" name=\"TEST\" onChange=\"parent.frames[3].location='2row.php?action=secondgroup&secondgroup=$TEST'\">";
echo "<option>Choose Type</option>";
while($row = mysql_fetch_row($result)) {
echo "<option value = \"$row[1]\">$row[1]</option>";
}
echo "</select></p>";

Anyway to do this without using a form? I undertand why it isnt working, but I cant figure out how to fix it. Thanks

[biggus]

Mike,
try this...

onChange=\"parent.frames{3].location='2row.php?type='+this.options[this.selectedIndex].text\"

Then, 2row.php will have a variable called $type with the text of the selected menu item.

[biggus]

oops...typo. frames{3] should be, of course, frames[3]. Got carried away with the caps key.

[Anon]

you can pass the value using the below finction

function change_contact()
{
clicked_value=document.support_call.client_contact[document.support_call.client_contact.selectedIndex].value;

if(clicked_value == '')
{
alert("Please select contact you want to view");
return false;
}
var newWindow;
var myurl="add_client_contact.php?client_id=" + clicked_value ;
var props = 'scrollBars=no,resizable=yes,toolbar=no,menubar=no,location=no,directories=no,width=350,height=400';
var newWindow = window.open(myurl, "Add_from_Src_to_Dest",props);
if (!newWindow.opener)
newWindow.opener = self;
if (newWindow.focus != null)
newWindow.focus();
}

Vinod Palan A
Calypso Technology, Inc.
[e-mail]
[phone] Phone