Number formatting (1 to 01 etc...)

[Anon]

Hi,
I've searched these forums a lot but am having difficulty finding how to format the date in a dropdown menu to list:

01
02
03
etc...

instead of:
1
2
3
etc...

Can anyone help? Heres the code to create the day dropdown menu:

---

$dob_days_list = "";

for ($i = 1; $i < 32; $i++)
{
$print_selected = "";
if ($i==$dob_day) {$print_selected = " SELECTED";}
$dob_days_list = $dob_days_list ."<OPTION VALUE=\"$i\"$print_selected>$i</OPTON>\n";

}

I've looked at the sprintf function but am totally confused!

[mistcat]

try
echo sprintf("%02d",$number);

[khaine]

In a very basic way you could use

$dob_days_list = "";

for ($i = 1; $i < 32; $i++)
{
$print_selected = "";
if ($i==$dob_day) {$print_selected = " SELECTED";}
if ( $i < 10 )
{
$dob_days_list = $dob_days_list ."<OPTION VALUE=\"0".$i."\"$print_selected>0".$i."</OPTON>\n";
}
else
{
$dob_days_list = $dob_days_list ."<OPTION VALUE=\"$i\"$print_selected>$i</OPTON>\n";
}
}

Mark.

[Anon]

That works a treat, thank you very much.

[[deleted]]

Use the sprintf method instead!!

[Anon]

Why, it works fine?

[Anon]

Why is Nate Parsons method better and if so, how can I use it with the code I put in the original message?

[[deleted]]

Why is it better.

well, for one thing, it's shorter: one line vs eight lines.

How do you use it (untested, my contain typos):

for ($i = 1; $i < 32; $i++)
{
$print_selected = "";
if ($i==$dob_day) {$print_selected = " SELECTED";}
$dob_days_list .= sprintf('<OPTION VALUE="%d" %s>%02d</OPTION>',$i, $print_selected, $i)."\n";
}

[Anon]

That works brilliantly thanks!