Unable to open local file for reading

[tobias]

Questions upon questions...

I wrote this upload script that is supposed to upload images to the webserver called "loader.php".

It works fine in a separate script, with a form action="loader.php".

Once I put it inside another script called alben.php it freaks out. I change the form action to "alben.php", and get this error msg:

Warning: getimagesize: Unable to open 'C:\Dokumente und Einstellungen\John Doe\Eigene Dateien\Eigene Bilder\nuee.jpg' for reading. in /home/user19/htdocs/temp/alben.php on line 74

What could possibly be wrong here?

Also, I pass a variable to this script, which shows in the address bar like:

http://whateverpath.com/temp/alben.php?album_id=1&totalimages=16

...still <?echo $album_id?> returns nothing...

I am going slightly mad...

[Anon]

Warning: getimagesize: Unable to open 'C:\Dokumente und Einstellungen\John Doe\Eigene Dateien\Eigene Bilder\nuee.jpg'

OK, that means that you're trying to access a Windows file, because of the C:\ drive.

for reading. in /home/user19/htdocs/temp/alben.php on line 74

OK, that means that you're on a UNIX type of server.

There's your error...you're trying to access a Windows file on a UNIX server...

Diego

[tobias]

But that doesn't make sense to me. I am only trying to upload a file.

I can access that file, no problem. With this script:

<form enctype="multipart/form-data" action="loader.php" method="POST">
<input type="hidden" name="MAX_FILE_SIZE" value="102400">
<table cellspacing="0" cellpadding="4" width="800" style="border-color:#000000;border-style:solid;border-width:1 1 1 1;font-family:verdana,helvetica,arial,sans-serif;font-size:9px;font-weight:bold;color:#000000;">
<tr>
<td>
<input name="userfile" type="file">
</td>
<td>
Beschreibung
<br>
<input type="text" name="description" size="60">
</td>
<td>
<input type="submit" name="newimage" value="Upload">
</td>
</tr>
<tr colspan="3">
<?echo $errorimage;?>
</tr>
</table>
</form>

<?
#Max. Size
$maxsize = 102400;

#Max. dimensions
$maxwidth = 800;
$maxheight = 600;

#Allowed Types
$allowed_types = "image/jpeg@image/pjpeg";

#Path
$path = "/home/user19/images/admin/1/";

if ($newimage == "Upload")
{
#Set new filename
$newfile = $path . $userfile_name;

#Get Imagesize
$imageinfo = getimagesize($userfile);

#Check filetype
if (!ereg($userfile_type, $allowed_types))
{
	$errorimage .= "Filetyp nicht zugelassen. Zugelassen sind nur ";

	$filetypes = explode("@", $allowed_types);

	#Reset counter
	$counter = 1;
	#Echo allowed types
	while (list($key, $value) = each ($filetypes))
	{
		$errorimage .= $value;
		if ($counter < count($filetypes))
		{
			$errorimage .= " und ";
			$counter++;
		}
	}
	$errorimage .= "!<br>\n";
}
#Check filesize
else if ($userfile_size > $maxsize)
{
	$errorimage .= "Datei zu gro&szlig;! Maximale Gr&ouml;&szlig;e: " . $maxsize/1024 . " kb!<br>\n";
}
#Check width
else if ($imageinfo[0] > $maxwidth)
{
		$errorimage .= "Das Bild ist zu breit! Max. Breite: " . $maxwidth . " Pixel!<br>\n";
}
#Check height
else if ($imageinfo[1] > $maxheight)
{
		$errorimage .= "Das Bild ist zu hoch! Max. H&ouml;he: " . $maxheight . " Pixel!<br>\n";
}
#Check if file exists
else if (file_exists($newfile))
{
		$errorimage .= "Ein Bild mit diesem Namen gibt es bereits in diesem Album!<br>\n";
}
#Copy and check
else if (!@copy($userfile, $newfile))
{
	$errorimage .= "Datei konnte nicht upgeloadet werden.<br>\n";
}
else
{
	$errorimage .= "Upload von $userfile_name erfolgreich!";
}

}
?>

Now, that works. As soon as I put this inside another script like this:

<?
session_start();

include ("functions.php");
include ("connect.php");

$ip = $REMOTE_ADDR;
$session_id = $PHPSESSID ."@" . $ip;
#Prüfen, ob die Session-ID mit der aktuellen $PHPSESSID übereinstimmt
$query = "SELECT session_id FROM users WHERE session_id = '$session_id' AND username = '$username'";
$result = safe_query($query);

#Wenn nicht -> überprüfe Username und Passwort
if (mysql_num_rows($result) < 1)
{
header("location: login.php");
}
else
{
include ("header.php");
include ("alben_formular.php");

#Include Upload Form
$query = "SELECT * FROM albums WHERE album_id = '$album_id' AND owner = '$username'";
$result = safe_query($query);

?>

... here is the above script (without the closing ?>...

}

include ("alben_show.php");
include ("footer.php");

}
?>

[Anon]

Anyone got any ideas? I am really a bit stuck...