check to see if $var is divisible by 2 ?

[mmilano]

I am making a simple table for an online gamming team. This table will show the members. It is 2 cells wide, then a new row starts.

I pull the team from a database into the table, but if there are an odd number of players, i need to add an extra empty cell to the code.

is there any function to check and see if a number is divisible by 2?

such as:
count($array);
if($array / 2) { do this; } else { do that; }

i know that is not accurate, but that is what i want. any ideas?

[mmilano]

error in my code.. it was meant to go like this:

count($array);
if($count / 2) { do this; } else { do that; }

[Anon]

Well, how would you do it in real life? You check for a remainder, right? If the remainder is 0, then it is divisible. If the remainder is anything else, it is not divisible. From what you know, you can do this:

function isDivisibleBy2($number) {
$quotient = $number / 2;
return ($quotient == floor($quotient));
}

This function divides by 2 and gets the result. If there is a remainder, then the quotient will have a decimal place. So ($quotient == floor($quotient)) will be false. But if the quotient is an integer, then the number is divisible by 2 and ($quotient == floor($quotient)) will return true.

But you can save all this hassle because PHP has a remained operator, %. So just use:

if ($number % 2 == 0)

Diego

[mmilano]

thank you for the schooling =)
it is greatly appreciated!