Variable scope (from function)

[Anon]

How do I "fix" this code so that the variable from inside the function is available outside of it once I've called it?

<?php
function Add($one, $two) {
$total = $one + $two;
}
Add(5,6);
echo $total;
?>

Thanks, Corey

[Anon]

Try adding "return"

<?php
function Add($one, $two) {
$total = $one + $two;
return $total;
}
Add(5,6);
echo $total;
?>

[Anon]

Thanks...