Problems using img src command

Anon

I am new to programming in PHP/MySQL, but in the space of a couple of weeks have managed to write a dynamic image gallery. Ok, nothing new there, but I have a problem I can't work out. I am using MacOS X with latest MySQL and PHP.

Imagine a Web site is setup at:
/library/webserver/documents/mywebsite

The "mywebsite" dir has three directories:
images
php_libraries
website

I have a PHP page called "gallery.php" in the "website" directory which calls a program called "thumbnail.php" situated in the "php_libraries" directory by using an include statement. The full path has been specified. This works without a problem. The function of the "thumbnail.php" program is to draw the thumbnails. It does this via the print command, setting a link for each graphic, and uses an img src for the graphic. However within the img src command is a call to another php program, also in the php_libraries dir. This other program basically consists of a header line specifying output is going to be Jpeg, and then a few commands to resize the normal size Jpeg to thumbnail size. The image is then passed back to the other program.

So all of this works without fault, dynamic generation of thumbnail images work. However if I create a subdirectory in the ""mywebsite" directory, and then move the "gallery.php" to run from there, the graphics then fail to display. Basically moving the "thumbnail.php" program to two directories "down" from the original causes problems.

Anyone any ideas?

Anon

how did you reference the "other program" inside the img src tag?

I assume you did something like this...
<img src='../php_libraries/image.php?image_id=1'>

Anon

Hi David

Thanks for replying. I posted this message on Zend.com as well, got some replies, so this is what I just posted in response.

Can you see anything that would cause a problem?

Here is the important bits of the code:

Firstly, the starting PHP page has the following:
<?PHP
$root_dir="..";
$website_dir="$root_dir"."/mywebsite";
$number_of_rows=3;
$images_per_row=3;
$thumbnail_ratio=4; $images_per_page=$number_of_rows*$images_per_row;
include ("$root_dir"."/php_libraries/thumbnail.php");
?>

Everything else in this program is HTML.

I have tried using the complete path such as /library/webserver etc in all places, and have done away with the two vars $root_dir and $website_dir altogether, but problem remains the same. I don't think the issue is I'm pointing to the wrong place.

Ok, thumbnail.php has the line:
print("<td align=\"center\"><a href=\"$website_dir/draw_image.php\"><img src=\"$root_dir/php_libraries/resize_image.php?temporary_data=$temporary_data&root_dir=$root_dir\"></a></td>\n");

The link works as expected, and if I replace the img src with a graphic name instead (i.e. image.jpg) which is in the dir php_libraries, it works.

And then resize_image.php looks like this:
<?PHP
Header("Content-type: image/jpeg");
$temporary_data=escapeshellcmd($temporary_data);
$src_img=ImageCreateFromJPEG("$root_dir"."/images/"."$temporary_data");
$original_size_x=imagesx($src_img);
$original_size_y=imagesy($src_img);
$new_size_x=$original_size_x/4;
$new_size_y=$original_size_y/4;
$dest_img=ImageCreateTrueColor($new_size_x,$new_size_y);
ImageCopyResized($dest_img,$src_img,0,0,0,0,$new_size_x,$new_size_y,$original_size_x,$original_size_y);
ImageJPEG($dest_img);
ImageDestroy($dest_img);
ImageDestroy($src_img);
?>