Load external HTML into variable?

[Anon]

Hi, i have this code, but it doens't seem to work...

---

#!/usr/bin/perl
print "Content-type: text/html \n\n";
$path = "search?hl=en&lr=&safe=off&q=foo+bar";
$fp = fsockopen("www.google.com",80,&$errno,&$errstr,10000);
fputs($fp, "GET $path HTTP/1.1\n");
while(!feof($fp)) {
$searchresults .= fgets($fp, 128);
}
fclose($fp);

print $searchresults;

I am a newbie. i want to load an entire url into a variable.. HOW???

[Anon]

This worked for me:

<?php
print "Content-type: text/html \n\n";
$path = "/search?q=foo+bar";
$fp = fsockopen("www.google.com",80,&$errno,&$errstr,10000);
fputs($fp, "GET $path HTTP/1.1\n\n");
while(!feof($fp)) {
$searchresults .= fgets($fp, 128);
}
fclose($fp);
print $searchresults;

?>

I added "/" to the $path and another line break here:
fputs($fp, "GET $path HTTP/1.1\n\n");

[Anon]

I assume that since this is a php forum you are trying to write a php script. Try this:

<?php
$fp = fsockopen ("www.php.net", 80, $errno, $errstr, 30);
if (!$fp) {
echo "$errstr ($errno)<br>\n";
} else {
fputs ($fp, "GET / HTTP/1.0\r\nHost: www.php.net\r\n\r\n");
while (!feof($fp)) {
$contents = fgets ($fp,128);
}
fclose ($fp);
echo $contents;
}
?>

(from the php manual http://www.php.net/manual/en/function.fsockopen.php)

[Anon]

I was trying to put PHP into a CGI script 🙂

it works now, thanx guys