cgi to php

Anon

Im now using a php script instead of a cgi script. The prob is that the cgi scrip used the singe quotes ' and php uses "

I was using this script to remove bad urls. This is what the cgi script looked like:

$sourcelink = '<a href="';
$newlink = '<a target=\"_blank\" href=http://entertainment.lycos.com/movies/';

the php does this:

$DataPrint[1] = str_replace( "<a href="", "<a target=\"_blank\" href=http://entertainment.lycos.com/movies/", $DataPrint[1]);

As you can see i have to use the double quotes within doubles with php and that gives me parse errors. Im not sure what single quotes do in php. Any ideas on what i can do?

Thanks,
Mark

P.S.
The php code works great as long as i dont have any double quotes within the other double qoutes. But i cant use it as well that way

Anon

Just in case that wasnt the prob, which im seeing here at this case, im getting an error with line 9. here is the full code

<?php

########################

Mandatory Setting

########################

$GrabURL = "http://entertainment.lycos.com/movies/"; //- Complete URL Of The Page Your Grabbing From!
$GrabStart = "At the Box Office</td></tr></table>"; //- HTML Code To Start Grab. Must Be A Unique Bit Of Code!
$GrabEnd = ""; //- HTML Code To End Grab. Must Be A Unique Bit Of Code!

#############################

Do Not Edit Below Here

#############################
$OpenFile = fopen("$GrabURL", "r"); //- DO NOT CHANGE
$RetrieveFile = fread($OpenFile, 200000); //- Reduce This To Save Memory
$GrabData = eregi("$GrabStart(.*)$GrabEnd", $RetrieveFile, $DataPrint);

$DataPrint[1] = str_replace( "<a href=\"", "<a target=\"_blank\" href=\"http://entertainment.lycos.com/movies/", $DataPrint[1]); //- Un-Comment This Line for "Replace" purposes!
#$DataPrint[1] = str_replace( "href=\"/avcenter/", "href=\"http://www.symantec.com/avcenter/", $DataPrint[1]); //- Un-Comment This Line for "Replace" purposes!
#$Dat#Print[1] = str_replace("", "", $DataPrint[1]); //- Un-Comment This Line for "Replace" purposes!
fclose($OpenFile); //- DO NOT CHANGE
echo $DataPrint[1]; //- DO NOT CHANGE
####################

End of Script

####################

Anon

Use backslashes before a quote inside a quote:

print "quote\"quote\"";

Diego

Anon

You can also use something like

print "quote 'quote'";

It doesnt matter when printing out html wether its a " or a ' and it makes for a somewhat less confusing script.

Although.. to each their own!

Cheers,

John

Anon

Thanks, that worked