How display images in php???

Anon

Hello,

I'm trying to display my images. It works in html but doesn't in php!
I'm working local for the moment using apache. Everything works except displaying my images. I can't display any image in my root! The root of my PHP pages is
"c:\phpweb" (doc_root).
For example in my root dir there's a picture test.gif.
So for testing I create a file img_test.php:

<?php
function fnc_img_path($img){
global $img_path;
$img_path = "$img";
}

echo(fnc_img_path('test.gif'));

print("<IMG src=\"$img_path\" width=133 height=178>");
?>

This code would normally display my image test.gif but it doesn't. My code will work if I copy for example the image under my c:\ and then change one thing in the code:
$img_path = "c:\$img";

I have the same problems with <bgsound src="test.mp3">! The sound will not play in the root, but when I set the mp3 anywhere else and change the path it 'll work. Also I can't use subfolders in my root (for ex. for my images, functions,...)!

Does anyone have an answer for me?
Please, it urgent!

Thanks in advance,
Boogey Man

Anon

Is there a reason you can't just write:

echo "<img src='./images/name.gif'>";

or even:

function img($name)
{
$imgpath = "C:\phpweb\pathimages\";
$image = $imgpath . $name;
echo "$image";
}

and then write

echo "<img src=\"";
img("test.gif");

echo "\">";

that seems much easier...

-Adam

Anon

Yes,

Maybe your code is better,thnx anyway. But that's not my problem. My problem is that I can't display images which are in my root. Whether there in a subfolder or not.

Greetz,
Boogey Man

Anon

Yo Adam,

when I run your code:
<?php
function img($name)
{
$imgpath = "C:\";
$image = $imgpath.$name;
echo "$image";
}

echo "<img src=\"";
img("test.gif");
echo "\">";
?>

the following error occur:
Parse error: parse error in c:\phpweb/test_img2.php on line 6

Any thougts?

Greetz,
Boogey Man

sethadam1

The $imgpath var should point to the path to the image directory, not the root of the C drive, which cannot be your webroot! The code below, for example, would display an image called test.gif in a directory called C:\webroot\images. It doesn't matter where the script is called. Make sure you leave the last / also.

<?php
function img($name)
{
$imgpath = "C:\webroot\images\";
$image = $imgpath.$name;
echo "$image";
}

echo "<img src=\"";
img("test.gif");
echo "\">";
?>

-Adam

Anon

Thnx Adam,

I copied the code and changed $imgpath = "C:\phpweb\images\";
where test.gif is in that folder.
Even when I test it on my c:\ to see if the function works fine it fails.

When i run the code the following error occur:
Parse error: parse error in c:\phpweb/test_img2.php on line 6

Greetz,
Boogey Man