Parse errors in printf statement

[Anon]

I keep getting parse errors in the code below and I'm not sure why.

This code is only a snippet that is included in a php file hence the missing database connection which is called by another include

<?php
// generate and execute query
$list_computername_sql = "SELECT cname,machid FROM inventory WHERE clientid='$clientid'";
$list_computername_result = mysql_query($list_computername_sql);

if($myrow = mysql_fetch_array($list_computername_result)){
do
{
printf("<a href=\"displaysystem.php?clientid=$clientid&machid=$myrow["machid"]\">$myrow["cname"])</a>\n";

}while ($myrow = mysql_fetch_array($list_computername_result));

}
else
{
echo"no results";
}

?>

[Anon]

Try it like this

printf("<a href=\"displaysystem.php?clientid=$clientid&machid=%s["machid"]\">%s["cname"]</a>\n", $myrow, $myrow);

[sfmnetsys]

I tried what you suggested, but I am still getting a parse error on the printf line.

[Anon]

Why are you using printf anyway? You're not using any of printf's specialty...

Try:

print "<a href=\"displaysystem.php?clientid=$clientid&machid=$myrow[machid]\">$myrow[cname])</a>\n";

You can't use double quotes inside double quotes.

Diego