How to convert echo to if statement

giovo

Can someone tell me how this works. I never understood those macho echo statements. Can someone show me the light?

echo "If this is correct print this ".($result ? "" : "not correct")."Else print this code that drives me crazy\n";

I don't get it. What does that mean:

.($result ? "" : "not correct")."

Any idea? Thanx.

maxxx

Giovo wrote:

Can someone tell me how this works. I never understood those macho echo statements. Can someone show me the light?

echo "If this is correct print this ".($result ? "" : "not correct")."Else print this code that drives me crazy\n";

I don't get it. What does that mean:

.($result ? "" : "not correct")."

Any idea? Thanx.

I'm not sure if I got your question, anyway
. means cat the following string
($result ? "" : "not correct") is a conditional expression in the form
a?b:c
meaning if (a) value is b else value is c
evaluation of $result as boolean maybe a sort of an havoc because it (the variable) could be a real boolean, with trivial meaning, a string with meaning "is empty or not", a number with meaning "is non zero", an array or object with other meaning and so on.

The equivalent code is
if ($result)
$@!#$ = "";
else
$@!#$ = "not correct";
echo "If this is correct print this $@!#$ Else print this code that drives me crazy\n";

blindtoad

It's called a tertiary operator. It's kind of a short hand way of doing an if, else statement. the first part is the test e.g. ($result). this must evaluate to true or false or (zero for false and 1 or greater for true) what follows the question mark is what gets used if the statement is true and what follows the colon is what gets used if its false. So, echo (1)?"hi":"bye"; will print hi and echo (o)?"hi":"bye"; will print bye. Hope this helps

giovo

A very big thanx to Maxxx & John for your explanations. A small clearing about this one $@!#$ is needed:

$@!#$ = "correct";
$@!#$ = "not correct";

I mean I have to use those always or... $@!#$ I never saw those signs. Whats that? I mean I found no such thing in manual/php.net/zend.com - nothing.

You mean by the standard:

$@!#$ = "correct";

is the same as:

$my_string = 'correct';
print('$my_string');

I'm asking you that because you said: The equivalent code is the one with $@!#$ ... Interesting.

maxxx

Sorry, no strange signs:
I wrote $s_h_i_t (without the _ ) and it seems there's a moderating filter that translated the bad word in strange symbols, just replace $@!#$ with $dumb
Sorry again, I ough not to be vulgar.
Maxxx

Anon

Thank you Maxxx,

You know I was looking all arround for the explanation,... & even asked some c programers,... Nobody had the cluest idea what that might be. One even said:"F--- I thought that I was more than just good in my pascal & c++, I have to reread all my books again. I'll let you know."

;-) I thought that that was a string name, but I was not 100% sure. Now I feel better. Thanks again for that one.