Drop down list filled from table colum?

[bike5]

I am trying to fill a drop down list with every name in my tables colum of names, I did:

$Query = "SELECT user_name from $TableName";
$Result = mysql_db_query($DBName, $Query, $Link);
$colum = mysql_fetch_array ($Result);
if(($user_logname) AND (!$submit)){
echo ("<select size=\"1\" name=\"emails\">");
echo ("<form method=\"POST\" action=\"email.php\">");
while ($colum = mysql_fetch_array ($Result)) {
echo ("<option>$colum[user_name]</option>");}
echo ' </select>';
echo("<p><input type=\"submit\" value=\"Submit\" name=\"submit\"><input type=\"reset\" value=\"Reset\" name=\"B2\"></p>");
echo '</form>';

This only puts out an emtpy drop down menu. Is there something I did wrong or need to do? I also wanted to sort the names alphabeticaly.
Thanks for your help.

[Anon]

Quite a few things wrong; instead of listing each fix it was a lot easier for me to do a rewrite.

if($user_logname && !$submit){
$Query="select user_name from $TableName order by user_name";
$Result=mysql_db_query($DBName,$Query,$Link);
$Result_num=mysql_num_rows($Result);

if($Result_num>0){
echo '<form method="post" action="email.php">');
echo '<select size="1" name='emails'>';

for($i=0;$i<$Result_num;++$i){
$column=mysql_fetch_array($Result);
echo "<option>$column['user_name']";
}

echo '</select>';
echo '<p><input type="submit" value="Submit" name="submit"><input type="reset" value="Reset" name="B2"></p>';
echo '</form>';
}
}

[Anon]

Nevermind the obvious bug on the <select line where I say 'emails' when I should've said "emails"