ereg_replace help needed urgently!

[Anon]

Given a certain URL such as:
/file.php?id=1&sid=abc123&prodid=12&img=b

How can I remove the variables id=1 and sid=abc123 from the URL ?
so I get: /file.php?prodid=12&img=b

(note that the id or sid variable may be anywhere within the URL string)

Thanks,
Jamie

[whizkid]

Hi,

try following:

function remove_vars($url, $vars) {
if(ereg("\?", $url)) {
$t = explode("?", $url);
$e = explode("&", $t[1]);
$var = array();
$val = array();
for($i=0; $i<count($e); $i++) {
$z = explode("=", $e[$i]);
$var[] = $z[0];
$val[] = $z[1];
}
if(count($var) != count($val)) {
return false;
}

while(list($k, $v) = each($vars)) {
  if(!ereg($v."\=", $url)) {
    return false;
    break;
  }
}
$c = 0;
$r = array();
for($j=0; $j<count($var); $j++) {
  if(!in_array($var[$j], $vars)) {
    $r[] = $var[$j]."=".$val[$j];
  }
}

} else {
return $url;
}
if(count($r) != 0) {
return $t[0]."?".implode("&", $r);
} else {
return $t[0];
}
}

echo "<pre>";
print(remove_vars('/file.php?id=1&sid=abc123&prodid=12&img=b', array('id', 'sid')));
echo "</pre>";

fiermouse2001