New PHP Version

[Anon]

Have a question for anyone. I have a page with a form.

<FORM Action="filename.php">
<INPUT TYPE="Text" NAME="state">
</FORM>

One my other page I have a SQL Statment retrieving records where State = $state.

With the new verson of php it does not work.

Anybody know why????

[Anon]

because you need $state to be a cookie

OR change the FORM ACTION to that other script name

OR put the SQL code in this file and do a:
if ($SUBMIT) {
$sql="....";

Hope that helps.

[Anon]

Why would they take functionality away from a previous version?

[Anon]

starting with 4.2.0 register_globals is now set to "Off" by default (for security reasons). You can either turn it back on (which is discouraged) or can reference your variable thru the new superglobal arrays:

$POST['state'] or
$GET['state'] depending on your form method

[Anon]

That makes sense. Now with hosting companies that are running a previous version, if they upgrade, that is going to affect all me code I am using now????? I will have to check my code. Thanks a bunch.

[Anon]

An easy way that I use to write scripts now is this:

At the top:

$POST = &$_POST;

and then I just use $POST in my scripts. If the server is running pre-4.1.0, I just change

$POST = &$_POST;

to

$POST = &$HTTP_POST_VARS;

without touching the rest of the program and it'll work fine in older versions.

Diego