Pasing php variables to java script

[pullez]

Hi everyone:

While developing my first dynamic site, I realized that I need to open a popup window with dynamic url:

-I have a $row[4] variable with an url value returned from mysql.I´m trying to assign this variable´s value to a java script window open function.

-This is what the code looks like:

$temp = $row[4];//url
printf("<script language=\"javascript\">");

printf("function liveWindow(temp){
var liveWindow4=window.open\"$temp\",liveWindow4,\"width=310,height=420,toolbar=no,location=no,status=no,menubar=no,scrollbars=yes,resizable=yes,directories=0,status=0,copyhistory=0,maximise=no,left=30,top=30\");}");
printf("</script>");
printf("<A HREF =\"javascript:onclick=liveWindow()\">Open new window</A>");
}

When clicked in the link that supposes to open the window all I got is the infamous 500 apache error wich basically means url not found.

Note:The url is a *.php page.

Thanks for your help in advance,
Jorge

[Anon]

Shouldn't there be a parenthesis after window.open?

window.open(\"$temp\",

Also, is there any reason you're using printf instead of just print?

Also, 500 errors are not page not found errors. Page not found errors are 404 - 500 is internal server error (meaning that the web server had an error while trying to do something, for example a PHP script failed)

Diego

[pullez]

Hi Diego:
I didn´t understood what you ment about the parenthesis.
About the 500 error you are actually right , but what I ment was Apache error_log:"premature end of script header" wich translates as file not found in most of the times.I guess the browser is making a request for a not found url as a result of the java script.

[pullez]

Actually yes there is a parenthesis It´s just a typo error when submitted.
Thanks.

[Anon]

Can we see the actual output of the script? Do you have the page up somewhere?

Diego