Simple parse error.

[cwspen]

Well I\'m trying to write a simple car expense tracking program. I\'m a novice at best.

What I want to do is load the page and if no sort variable is declared, sort by mileage.

If there is a sort variable defined, sort by that column.

What I have:

  if (!$sort) {
    sort_mileage();
  }
  elseif ($sort==\"litres\") {
    sort_litres();
  }

However when the page first loads, $sort isn\'t defined and I get a parse error.

This can be witnessed here: http://www.cameronspencer.com/car_program/index.php

However, as soon as you click on a column header (and define a value for $sort) it works as it should.

So how can I check for $sort without getting the parse error?

Thanks.

[Anon]

You're not getting a parse error, it's just a warning. If you get a parse error, the page won't even load.

Anyway, to solve that you'd need to use isset():

if (!isset($sort)) {
sort_mileage();
}
elseif ($sort=="litres") {
sort_litres();
}

Diego

[cwspen]

Thank you very much.

[cwspen]

One more quick question.

In my database I have values for total cost.

i.e. 5, 5.1, 13, 31.07, etc.

I want them to display as dollar amounts with two decimal places.

What's the best way to achieve this?