Netscape 4 Check

[Anon]

Apparently NS4 doesn't support form elements using Style Sheets...sooo, what I need to do is run a check for NS4 in my header file...some pseudocode:

if (!ns4) {
print form style sheet stuff here...
}

Anyone got a few lines to check for NS4 filling in the !ns4 above? The only scripts I've found seem to be 50 lines. This isn't a real high priority thing, just thought someone might have a snippet offhand.

TIA!

[Anon]

Sometimes it's easier on clientside:

<script language="javascript" type="text/javascript">
<!-/ if (document.layers) //Netscape 4.x was not full CSS compliant! {document.write('<link rel="stylesheet" type="text/css" ref="n_styles.css">');}
else {document.write('<link rel="stylesheet" type="text/css" ref="styles.css">');}
//-->
</script>

[Anon]

Thanks, but I really need a PHP version. This will go inside the <style> code, so I don't think it would be possible/wise to use Javascript.

[Anon]

Then happy playing with preg_match...
Or try using get_browser()
But everything will fail if the client uses webwasher or similar "tools" - as far as I know (I really don't know much...)