Instantiating Class with Variable Name?

[trube]

Is it possible to instantiate a class using a variable as the class name? For example, I tried to instantiate a class from within another class using the following:

$db = new $this->dbclass;

$this->dbclass was set to the name of the class I was trying to instantiate. But it didn't work.

I also tried using a constant as the class name as follows:

define ("DBCLASS", $this->dbclass);
$db = new DBCLASS;

But that didn't work.

What's the best way to do this?

[tomhath]

You could "eval" it. Check the manual under Miscellaneous Functions).

<?php

class test {
var $myname;
function test ($e) {
$this->myname = $e;
}
}

$cname = "test";
$estring = "\$obj = new $cname (\"AAA\");";
eval ($estring);
echo $cname . "<BR>";
echo $obj->myname . "<BR>";
?>