Preg Replace - No ending delimiter ....

[tappy]

hi !

Im a little stuck here and im unsure where to go, so I came here 🙂

This is my first ever try at something like this....

Ive got:

<?
print "<table border=\"1\" bordercolor=\"#CCCCCC\">";

$list = "1 Tux 14:15:7 54.990";

list( $rank, $name, $x, $y, $z, $score ) = split( '[:.-]', $list ) ;

$score = preg_replace ( '.' , ',' , $score ) ;

echo "<tr>\n
<td>$rank</td>\n
<td>$name</td>\n
<td>$x:$y:$z</td>\n
<td>$score</td>\n
</tr>\n";

print "</table>" ;

?>

But I keep getting the error:
Warning: No ending delimiter '.' found in my_parser.php on line 8

Line 8 is:
$score = preg_replace ( '.' , ',' , $score ) ;

Can anyone help please?

Ben

[tappy]

got it a little better:

<?
print "<table border=\"1\" bordercolor=\"#CCCCCC\">";

$list = "1 Tux 14:15:7 54.990";
list( $rank, $name, $x, $y, $z, $score ) = split( '[ :]', $list );
$score = preg_replace ('.', '', '$score');
echo "<tr>\n
<td>$rank</td>\n
<td>$name</td>\n
<td>$x:$y:$z</td>\n
<td>$score</td>\n
</tr>\n";

print "</table>" ;

?>

still get the same error tho

[Anon]

1) you need delemiters:preg_replace ( '/./' , ',' , $score ) ;
2) . is a special meaning char, matches every char! --> /.
preg_replace ( '/./' , ',' , $score ) ;

Now it should work....