identifying the [?]

Anon

This is a portion of my code:
$normalSearchSplit = split(" ", $normalSearch);
printf(" You Searched: %s ", $normalSearch);
$c = 0;
while($c)
{
do such and such
}

$normalSearchSplit would produce the results: $normalSearchSplit[0], $normalSearchSplit[1], etc..so and so forth.

$c represents the number inbetween the brackets [*]. I want the while statement to repeat until there is no $normalSearchSplit is through splitting and there is no more $c. How do I do this?

Anon

$normalSearchSplit=explode(' ',$normalSearch);
print(" You searched: $normalSearch ");
foreach($normalSearchSplit as $c=>$s)
{
do such and such
}

And in the loop you have $c running from 0 to however high it goes (namely, the number of words in $normalSearch minus one), and $s, equal to $normalSearchSplit[$c]

Anon

that makes sense but here's another stupid question. $normalSearch is the result from an input field, how would I calculate how many words they input so I can set $s

Anon

Don't need to - $c and $s are set by the foreach() loop.

What explode() (and split(), but more expensively) does is takes its input, explodes (or splits) it and puts all the fragments into an array (keeping them in the same order - it's a very tidy explosion), which it returns. If you want to know how many fragments there are, just use count() on the array.

Anon

I meant to add, if you do have something like $wordcount=count($normalSearchSplit), you can use an ordinary loop, like

for($i=0; $i<$wordcount; ++$i)
{}

Which is exactly equivalent to

$i=0;
while($i<$wordcount)
{
...
$i++;
}

But then the bits that control your loop end up getting scattered all over the place.

Anon

thanks