parse_url question

[Anon]

Hi all,
If i have the following code:

if ( $row['url'] != "" ) {
echo "<br><br>";
$urls = explode(", ", $row[url]);
for ($i = 0; $i < count($urls); $i++) {

echo "<a href=$urls[$i] target=\"_blank\">$urls[$i]</a><br>";
}

how can i include the parse_url function to dispaly only the 'scheme' and 'host'.
I've tried about 10 different ways but to no avail.

Any ideas?
Cheers,
maccam

[Anon]

I'm not quite sure what is being asked, but I use this to keep track of URL's and keywords:

$url_ar = parse_url($HTTP_REFERER);
$url_host=$url_ar[host]; // Referring host
$url_query=$url_ar[query];// this would be where your search engine's variables would appear
$url_path=$url_ar[path]; // the path of the referring script

[Anon]

Thanks for the reply,

I've tried the following:

}
if ( $row['url'] != "" ) {
echo "<br><br>";
$urls = explode(", ", $row[url]);
$url_parts = parse_url($urls);
$host = $url_parts['scheme'] . "://" . $url_parts['host'];
for ($i = 0; $i < count($urls); $i++) {
echo "<a href=$urls[$i] target=\"_blank\">$host</a><br>";
}

its almost working correctly but instead of displaying the "scheme" and "host" from the parse_url fuction it is only displaying the ://

Any ideas how to fix this?