OK. I have placed the following within my script:
$result = mysql_query( "SELECT url FROM table WHERE id = $id" );
I am now getting an error on the line that states the following:
while ( $a_row = mysql_fetch_row( $result ) ) {
Any suggestions? This is the exact error code:
Warning: Supplied argument is not a valid MySQL result resource in /home/mastero4/public_html/verify2.php on line 129
Thanks,