PHP and include

Anon

Hello everyone,

Here is my problem :

Let's assume we have a file file1.php with this code :

define("TEST_DEF", 0) ;
$testVar = 0 ;
include "file2.inc.php" ;

The problem is that in file2.php, neither TEST_DEF, nor $testVar exists ! Why ?

And if so, how can I fix that ?

Anon

Of course, it is

include "file2.php"
and not
include "file2.inc.php"

In fact, the problem occurs when I have a call like

include "file1.php" ;

which normally include file2.php.

alfoxy

Try include('file2.php'); -> the brackets

Is file2 being shown at all ?

Anon

In fact, the file is included.

But what I don't understand is why the constant and the variable have no value.

alfoxy

try this

file.php

include('varset.php');

echo "Test = $test";

vartest.php

$test = "It works !!";

if that dont work then its beyond my help

Anon

Test = It works !!

My real problem is :

index.php

include "include.inc.php" ;

include.inc.php

$test = "It works !!"
include "incl1.inc.php" ;

include "incl2.inc.php" ;

incl1.inc.php

echo "Test = $test" ;
function foo($value)
{
echo "foo -> $value" ;

}

incl2.inc.php

foo(3) ;

I have two problems :
- $test does not have any value in incl1.inc.php ;
- foo is not defined in incl2.inc.php

What is the matter ???

Anon

Come on... ;]

colbec

Is the included file in php mode? I.e. are you referring to your variables where php can see them?

icaro

i believe that Colin's message means php-start-end simbols must apear on includes,

are you using it?

main.php contains

(?php // ~ start php code

include 'code.inc.php';
foo($a);

?> ~ end php code

code.inc.php contains

(?php
include 'vars.inc.php';
function foo($b) {
echo '$a = ', $b;
}
?)

and vars.inc.php contains
(?php
$a = '-pi';
?)