Array of an undefined number of vars

Anon

I have something like
$product1, $product2, $product3, etc... $productN
where "N" varies according to the selection made before.

I'd like to know whether this is possible to create an array
containing all the $product (being aware that "N" is not a fixed value but is known),
so that I can then loop through all the values of all the $product.

Basically, I'd like to be able to make a loop that looks like:
foreach ($product ...) { //So here, $product1, $product2 until $productN would be considered one by one.

Thanks in advance!
Bruno

Anon

Use a loop and isset() to get all the $product# and put them into an array named $product...which part are you having trouble with, specifically?

Diego

plasko

Try this:

$product1 = "Hello";
$product2 = " my";
$product3 = " name";
$product4 = " is";
$product5 = " pete.";

$i=1; //assuming $product1 is the start
while(${product.$i})
{
echo ${product.$i};
$i++;
}

This might be more helpful for helping you understand the very flexible nature of variables used in php, although it should be a solution to your problem as well.

You can have any number of variables called $productN, but they have all follow that naming convention. The example makes is dynamically creating a variable name, and is assuming that the names will be in order. When there ceases to be a $productN, the loop will exit.

Let me know if this helps. If not, we'll figure something else out.

-pete

Bruno wrote:

I have something like
$product1, $product2, $product3, etc... $productN
where "N" varies according to the selection made before.

Basically, I'd like to be able to make a loop that looks like:
foreach ($product ...) { //So here, $product1, $product2 until $productN would be considered one by one.

Thanks in advance!
Bruno

Anon

Yep, this is exactly what I meant, I was looking for the way to display this:
${product.$i}

I didn't it was possible...

Thanks a lot, it does help a lot!
Bruno

Anon

I have now a small problem linked to this.
In the parts of code below, let's consider I have a loop for each value of $i.

If I do this, it works:
echo("The product found is " . ${'product'.$i} . "<BR>");

But if, on the same page, I try to insert all the $product variables in the database, it does not work:
db_query("
INSERT INTO products (product_id, product)
VALUES ( '$productid','${'product'.$i}')");

I get an error message saying that $product1, $product2, etc... "is not a defined variable"...

Does it have to do with the fact that I use additional single quotes for the SQL query?
How can I fix it?

Thanks in advance!
Bruno